无码av一区二区三区无码,在线观看老湿视频福利,日韩经典三级片,成 人色 网 站 欧美大片在线观看

歡迎光臨散文網(wǎng) 會員登陸 & 注冊

測試WizardMath-70B-V1.0

2023-08-20 19:19 作者:飛嘣的牛  | 我要投稿

1、提問

Below is an instruction that describes a task. Write a response that appropriately completes the request.

##?

Instruction:Given a triangle ABC, construct, using straightedge and compass, a point K on AB and a point M on BC, such that AK=KM=MC

###?

Response:Let's think step by step.


2、回答

Step 1: Construct the triangle ABC.

First, we need to draw the triangle ABC with vertices A, B, and C.


Step 2: Construct the midpoint of BC.

To find the midpoint of BC, we can use the midpoint formula. The midpoint M of a line segment with endpoints (x1, y1) and (x2, y2) is given by the coordinates ((x1 + x2) / 2, (y1 + y2) / 2). In this case, M is the midpoint of BC, so we can find its coordinates by averaging the x and y coordinates of B and C.


Step 3: Construct the point K on AB.

Now, we need to find a point K on AB such that AK = KM. Since KM = MC, this means that AK = MC. To find this point, we can use the concept of similar triangles. If we can construct a point K on AB such that triangle AKM is similar to triangle CKM, then AK = MC.


Step 4: Find the ratio of AM to MC.

To make the triangles similar, we need to find the ratio of AM to MC. Since M is the midpoint of BC, AM = MC/2. Therefore, the ratio of AM to MC is 1/2.


Step 5: Construct the point K using the ratio.

Now, we can use the ratio to find the point K. Since AM = MC/2, we can find K by going half the distance from A to M along the line segment AM. In other words, K is the point on AM such that AK = AM/2.


Step 6: Verify the construction.

We can verify our construction by checking that AK = KM = MC. Since AK = AM/2 and AM = MC/2, we have AK = MC/4. Also, KM = MC/2. Therefore, AK = KM = MC/4, which is not equal to the given condition AK = KM = MC.


Conclusion: It is not possible to construct the point K on AB and the point M on BC such that AK = KM = MC using only a straightedge and compass.


最后一點打不完,就不放了,有興趣可以去github上試

測試圖


測試WizardMath-70B-V1.0的評論 (共 條)

分享到微博請遵守國家法律
桦甸市| 乐平市| 容城县| 瑞安市| 汶上县| 洛南县| 鹤山市| 丹阳市| 定南县| 祥云县| 巨野县| 保德县| 渭南市| 陆丰市| 大庆市| 梅州市| 襄垣县| 双柏县| 桐城市| 新平| 长治市| 龙里县| 当涂县| 桂阳县| 宁海县| 玉环县| 玉树县| 新建县| 潍坊市| 乌什县| 中牟县| 青海省| 绍兴县| 崇左市| 邯郸市| 濉溪县| 安平县| 天长市| 开江县| 灵武市| 清苑县|